Newbie. Typed in 6 people. How to start again with gedcom

+1 vote
61 views
Hi

I have just joined. I started to type in my tree. However, I have a tree on ancestry.com. I have downloading this. How to a delete what I have added and start again.
in WikiTree Help by Sharon McArthur G2G Rookie (290 points)

2 Answers

+3 votes

Hey S,

Welcome. You cannot delete profiles. WikiTree uses a unique profile per person. That is very different from Ancestry where there are possibly many many duplicates for the same person.

A quick way to find connections is to export a GedCom from Ancestry and use the GedCompare system here at WikiTree. That will search for matching profiles here on WikiTree. Easy, as the ones you have entered should be connected then.

See the help page on GedComs. https://www.wikitree.com/wiki/Help:GEDCOM

Please make sure all profiles are well sourced and include good locations/dates. Without that, the matching is going to be harder. If you need more help, then contact your greeter (oh, that's me ;) ).

Moderator corrected name of gedcompare tool. 

by Michel Vorenhout G2G6 Pilot (223k points)
edited by Jillaine Smith

A good start reading point about the one tree idea is this page: https://www.wikitree.com/wiki/Help:Collaborative_Family_Tree

Thanks Jillaine.
+4 votes
When you upload your GEDCOM, then go through your GEDCompare report, the profiles you've already created will show up as "matches" which you just need to accept so you will not create duplicates. Once you go through your entire GEDCompare report and accept or reject all potential matches, you will get "ADD" buttons next to each individual for whom you did not mark a match to start creating profiles. If your GEDCOM is very large, it will take you a while to complete the GEDCompare process. Though you can create profiles this way be prepared--those profiles will need to be "cleaned" of what is referred to as "GEDCOM junk" and your sources may have to be reformatted to make sense and be useful to anyone.
by Nelda Spires G2G6 Pilot (353k points)

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